Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumMedium2 minPYQ_2024

PhysicsMediumsingle choice

A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m . The height of the table from the ground is 0.8 m . If the angular speed of the particle is $12 rad s^{- 1}$ , the magnitude of its angular momentum about a point on the ground right under the centre of the circle is

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Answer:

Solution:

Angular momentum $L_{0} = mvr sin 9 0^{\circ}$ $= 2 \times 0.6 \times 12 \times 1 \times 1$ $[$ As $V = r ω$ , $Sin 9 0^{\circ} = 1]$ So, $L_{0} = 14.4 kgm^{2} / s$

Stream:BITSATSubject:PhysicsTopic:RotationSubtopic:Angular momentum

⏱ 2mℹ️ Source: PYQ_2024

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