Start Free Mock LoginAlready registered? Login here

Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumMedium2 minPYQ_2023

PhysicsMediumsingle choice

A particle of mass $m$ is projected at a velocity $u$ , making an angle $θ$ with the horizontal ( $x$ -axis). If the angle of projection $θ$ is varied keeping all other parameters same, then magnitude of angular momentum (L) at its maximum height about the point of projection varies with $θ$ as,

Options:

Answer:

Solution:

Hint :
$L_{0} = m u cos θ H = m u cos θ \frac{u ^{2} sin ^{2} θ}{2 g} = \frac{m u ^{3} sin ^{2} θ cos θ}{2 g}$ $L$ is zero for $θ = 0^{\circ}$ and $θ = \frac{π}{2}$

Stream:WBJEESubject:PhysicsTopic:RotationSubtopic:Angular momentum

⏱ 2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...