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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Hard2 minPYQ_2023

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A thin wire of length ' $L$ ' and uniform linear mass density ' $m$ ' is bent into a circular coil. The moment of inertia of this coil about tangential axis and in plane of the coil is

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Solution:

$∴$ Moment of inertia of thin wire: $I M R ∴ I I = \frac{MR ^{2}}{2} = V \times m and L = 2 π R = \frac{L}{2 π} = \frac{Lm}{2} (\frac{L}{2 π})^{2} = \frac{mL ^{3}}{8 π ^{2}}$ $∴$ Using Parallel axis theorem: $I^{'} = I + M R^{2} I = \frac{m L ^{3}}{8 π ^{2}} + L m (\frac{L}{2 π})^{2} I = \frac{3 m L ^{3}}{8 π ^{2}}$

Stream:MHT_CETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2023

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