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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalEasy2 minPYQ_2022
PhysicsEasysingle choice

A solid cylinder and a solid sphere, having same massMand radiusR, roll down the same inclined plane from top without slipping. They start from rest. The ratio of velocity of the solid cylinder to that of the solid sphere, with which they reach the ground, will be

Options:

Answer:
D
Solution:

During pure rolling, the work done by the friction is zero. Therefore, we can apply conservation of mechanical energy.

mgh=12mv2+12IvR2

mgh=12m+IR2v2

v=2gh1+ImR2

For a solid cylinder ImR2=12 and for a solid sphere, ImR2=25

vCylvSph=1+251+12=1415

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational
2mℹ️ Source: PYQ_2022

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