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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Medium2 minPYQ_2021

PhysicsMediumsingle choice

Three solid spheres each of mass ' $M$ ' and radius ' $R$ ' are arranged as shown in the figure. The moment of inertia of the system about YY' will be

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Answer:

Solution:

Moment of inertia of the upper sphere $= \frac{2}{5} MR^{2}$ For each lower sphere M.I. $= \frac{2}{5} MR^{2} + MR^{2} = \frac{7}{5} MR^{2}$ $∴$ Total moment of inertia $I = \frac{2}{5} MR^{2} + 2 \times \frac{7}{5} MR^{2} = \frac{16}{5} MR^{2}$

Stream:MHT_CETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2021

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