TestHub
TestHub

Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2021
PhysicsEasysingle choice

The figure shows two solid discs with radius R and r respectively. If mass per unit area is the same for both, what is the ratio of MI of bigger disc around axis AB (Which is to the plane of the disc and passing through its centre) of MI of smaller disc around one of its diameters lying on its plane? Given M is the mass of the larger disc.

(MI stands for a moment of inertia)

Question diagram: The figure shows two solid discs with radius R and r respect

Options:

Answer:
D
Solution:

Ratio of the moment of inertia =12MR214mr2

=2σπR2R2σπr2r2=2R4r4

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...