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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2021

PhysicsEasysingle choice

The moment of inertia of a thin uniform rod of mass ' $M$ ' and length ' $L$ ' about an axis passing through a point at a distance $\frac{L}{4}$ from one of its ends and perpendicular to the length of the rod is

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Solution:

The moment of inertia of the rod about an axis passing through the center and perpendicular to its length is given by $I_{0} = \frac{ML ^{2}}{12}$ Hence by parallel axis theorem, $I = I_{0} + M (\frac{L}{4})^{2} = \frac{ML ^{2}}{12} + \frac{ML ^{2}}{16} = \frac{7 ML ^{2}}{48}$

Stream:MHT_CETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2021

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