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PhysicsRotationTorque / angular accelerationMedium2 minPYQ_2021
PhysicsMediumnumerical

A force F=4i^+3j^+4k^ is applied on an intersection point of x=2 plane and x-axis. The magnitude of torque of this force about a point 2,3,4 is ________.

(Round off to the Nearest Integer)

Answer:
20.00
Solution:

τ=r×F

r=2i^-2i^+3j^+4k^=-3j^-4k^

and F=4i^+3j^+4k^

τ=r×F=i^j^k^0-3-4434

=i^-12+12-j^0+16+k^0+12

=-16i^+12k^

 |τ|=162+122=20

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration
2mℹ️ Source: PYQ_2021

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