Physics - Rotation Question with Solution | TestHub

$\text{I}\left(about{\text{YY}}^{\prime }\right)=\frac{\text{m}{\ell }^2}{12}$

Using parallel axis theorem :

$\text{I (about AD)}=\frac{\text{m}{\ell }^2}{12}+\frac{\text{m}{\ell }^2}{4}=\frac{\text{m}{\ell }^2}{3}$