Find the torque about the origin when a force of 3 j ^ N acts on a particle whose position vector is 2 k ^ m .NEET 2020 (Phase 1)

F → = 3 j ^ N , r → = 2 k ^ τ → = r → × F → = 2 k ^ × 3 j ^ = 6 ( k ^ × j ^ ) = 6 ( - i ^ ) τ → = - 6 i ^ N m

Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationEasy2 minPYQ_2020

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Find the torque about the origin when a force of $3 \hat{j} N$ acts on a particle whose position vector is $2 \hat{k} m$ .NEET 2020 (Phase 1)

Answer:

Solution:

$\vec{F} = 3 \hat{j} N, \vec{r} = 2 \hat{k}$

$\vec{τ} = \vec{r} \times \vec{F} = 2 \hat{k} \times 3 \hat{j} = 6 (\hat{k} \times \hat{j})$

$= 6 (- \hat{i})$

$\vec{τ} = - 6 \hat{i} N m$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2020

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