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Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle of mass $5 g$ is moving with a speed of $3 \sqrt{2} c m s^{- 1}$ in X-Y plane along the line $y = x + 4$ . The magnitude of its angular momentum about the origin in $g c m^{2} s^{- 1}$ is

Options:

Answer:

Solution:

Given $y = x + 4$

When $x = 0, y = 4 c m$

And $y = 0, x = - 4 c m$

Perpendicular distance

$O C = O A \sin 45^{o} = 4 \times \frac{1}{\sqrt{2}} = 2 \sqrt{2} c m$

Angular momentum

$= m v (O C) = 5 (3 \sqrt{2}) (2 \sqrt{2})$

$= 60 g m c m^{2} s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Angular momentum

⏱ 2mℹ️ Source: PYQ_2020

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