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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle of mass $m = 1 kg$ is projected on a horizontal surface with speed $u = 20 \sqrt{2}$ $m s^{- 1}$ at an angle $45^{o}$ with horizontal. Find the torque of the weight of the particle about the point of projection when the particle is the highest point. Take $g = 10 m s^{- 2}$

Options:

Answer:

Solution:

$τ = \frac{m g R}{2} = \frac{(m g) u^{2} \sin 2 θ}{2 g}$

$= \frac{m u^{2}}{2}$ $(a s θ = 45^{o})$

$= \frac{(1) {(20 \sqrt{2})}^{2}}{2}$

$= 400 N m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2020

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