Physics - Rotation Question with Solution | TestHub

Moment of inertia of solid cylinder about$O,$

$I_{CM}=\frac{1}{2}M{R}^2$

Moment of inertia about point of contact$P, I_P=I_{CM}+M{R}^2$(using parallel axis theorem)

$=\frac{1}{2}M{R}^2+M{R}^2=\frac{3}{2}M{R}^2$