Two thin uniform rings made of the same material and of radii $R$ and $4 R$ are joined as shown. The mass of the smaller ring is $m$ . Find the moment of inertia of the system about an axis passing through the centre of mass of bigger ring and perpendicular to the plane.

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Answer:

B

Solution:

$I = I_{l arger} + I_{s m a l l e r}$
$I = 4 m {(4 R)}^{2} + [m R^{2} + m {(5 R)}^{2}] = 90 m R^{2}$

TestHub · Accepted Answer

I = I l arger + I s m a l l e r I = 4 m ( 4 R ) 2 + m R 2 + m ( 5 R ) 2 = 90 m R 2

Physics - Rotation Question with Solution | TestHub

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