Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsEasy2 minPYQ_2020

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The moment of inertia of a body about a given axis is $1 .2 kg m^{2}$ . Initially, the body is at rest. In order to produce a rotational KE of $1500 J$ , the angular acceleration of $25 r a d s^{- 2}$ must be applied about that axis for a duration of

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Answer:

Solution:

$I = 1.2 k g m^{2}$

$ω_{i} = 0$ ; $α = 25 rad s^{- 2}$

Rotational KE $= \frac{1}{2} {Iω}_{f}^{2} = 1500 J$

$\Rightarrow ω_{f} = 50 rad s^{- 1}$

$\Rightarrow t = \frac{ω_{f} - ω_{i}}{α} = \frac{50}{25} = 2 s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2020

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