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Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A one rupee coin starting from rest rolls down a distance of $1 m$ on an inclined plane at an angle of $30 °$ with the horizontal. Assuming that $g = 9.8$ $m s^{- 2}$ , the time taken is

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Answer:

Solution:

$l = 1 m, θ = 3 0^{o}, g = 9.81 m s^{- 2}, t = ?$

$K^{2} = \frac{1}{2} R^{2}$

$a = \frac{9.81 \times \frac{1}{2}}{1 + \frac{1}{2}} = \frac{4.9 \times 2}{3}$

$\Rightarrow$ $l = \frac{1}{2} a t^{2}$

$\Rightarrow 1 = \frac{1}{2} \times \frac{4.9}{3} \times 2 \times t^{2}$

$\Rightarrow t = \sqrt{\frac{3}{4.9}} = 0.7 s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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