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Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsEasy2 minPYQ_2020

PhysicsEasysingle choice

A thin uniform rod of length $l$ and mass $m$ is swinging freely, about a horizontal axis passing through its end. Its maximum angular speed is $ω$ . The maximum height, to which its centre of mass rises, is

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Answer:

Solution:

$T E_{i} = T E_{r}$

$\frac{1}{2} I ω^{2} = m g h$

$\frac{1}{2} \times \frac{1}{3} m l^{2} ω^{2} = m g h$

$\Rightarrow$ $h = \frac{1}{6} \frac{l^{2} ω^{2}}{g}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2020

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