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Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsEasy2 minPYQ_2020

PhysicsEasysingle choice

A ring of mass m and radius R has three particle attached to the ring as shown in the figure. The centre of the ring has a speed v₀. The kinetic energy of the system is (slipping is absent).

Options:

Answer:

Solution:

$KE = \frac{1}{2} m (v_{0}^{2}) + \frac{1}{2} ({mR}^{2}) {(\frac{v_{0}}{R})}^{2}$

$= \frac{1}{2} (3 m) {(\sqrt{2} v_{0})}^{2} + \frac{1}{2} (m) {(2 v_{0})}^{2}$

$= 6 m v_{0}^{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2020

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