Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsEasy2 minPYQ_2020

PhysicsEasynumerical

One end of a straight uniform $1 m$ long bar is pivoted on horizontal table. It is released from rest when it makes an angle $30^{o}$ from the horizontal (see figure). Its angular speed when it hits the table is given as $\sqrt{n} r a d s^{- 1}$ , where $n$ is an integer. The value of $n$ is ____________

Answer:

15.00

Solution:

according to energy conservation

$m g \frac{l}{2} \sin 30 ° = \frac{1}{2} \frac{m l^{2}}{3} ω^{2}$
Solving
$ω^{2} = 15$
$ω = \sqrt{15}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2020

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