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PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Four rods of equal length $ℓ$ and mass $m$ each from a square as shown in figure. Moment of Inertia about three axes 1, 2 and 3 are say $I_{1}, I_{2}$ and $I_{3} .$ Then, match the following

	Table-1		Table-2
$(A)$	$I_{1}$	$(P)$	$\frac{4}{3} {mℓ}^{2}$
$(B)$	$I_{2}$	$(Q)$	$\frac{2}{3} {mℓ}^{2}$
$(C)$	$I_{3}$	$(R)$	$\frac{1}{2} {mℓ}^{2}$
		$(S)$	$None$

Options:

Answer:

Solution:

$I_{1} = 2 (\frac{{mℓ}^{2}}{12}) + 2 (m) {(\frac{l}{2})}^{2} = \frac{2}{3} {mℓ}^{2}$

$I_{2} = 0 + 2 (\frac{{mℓ}^{2}}{3}) + {mℓ}^{2} = (\frac{5}{3}) {mℓ}^{2}$

$I_{3} = 4 [\frac{{mℓ}^{2}}{3} {sin}^{2} 45^{ο}] = \frac{2}{3} {mℓ}^{2} = I_{1}$

NOTE : $I_{1} = I_{3} (think why ?)$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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