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Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumEasy2 minPYQ_2020

PhysicsEasysingle choice

A thin circular ring of mass $M$ and radius $R$ rotates about an axis through its centre and perpendicular to its plane, with a constant angular velocity $ω$ . Four small spheres each of mass $m$ (negligible radius) are kept gently to the opposite ends of two mutually perpendicular diameters of the ring. The new angular velocity of the ring will be

Options:

Answer:

Solution:

According to conservation of angular momentum,

$Iω =$ constant,

hence we can write

$I_{1} ω_{1} = I_{2} ω_{2}$

or ${MR}^{2} ω = (M + 4 m) R^{2} ω_{2}$

or $ω_{2} = (\frac{M}{M + 4 m}) ω$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Angular momentum

⏱ 2mℹ️ Source: PYQ_2020

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