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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2020

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If the spherical planet of mass ' $M^{'}$ and radius 'R' suddenly shrinks to half its size, its mass reduces to half. The new moment of inertia of the planet about its diameter is

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Answer:

Solution:

$I_{1} = \frac{2}{5} MR^{2}$ $I_{2} = \frac{2}{5} \frac{M}{2} \times (\frac{R}{2})^{2} = \frac{2}{5} \times \frac{M}{2} \times \frac{R ^{2}}{4} = \frac{M R ^{2}}{20}$

Stream:MHT_CETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2020

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