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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minPYQ_2019

PhysicsMediumsingle choice

A disc of radius $2 m$ and mass $100 k g$ rolls on a horizontal floor. Its centre of mass has speed of $20 c m s^{- 1} .$ How much work is needed to stop it?NEET 2019 (All India)

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Answer:

Solution:

Energy of the cylinder $= \frac{1}{2} m v^{2} + \frac{1}{2} I ω^{2}$
$= \frac{1}{2} m v^{2} + \frac{1}{2} \frac{m r^{2}}{2} \frac{v^{2}}{r^{2}}$
$= \frac{3}{4} m v^{2}$
$= \frac{3}{4} \times 100 \times {(20 \times 10^{- 2})}^{2}$
$= 3 J$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: PYQ_2019

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