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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationHard2 minPYQ_2019

PhysicsHardsingle choice

A solid cylinder of mass $2 k g$ and radius $4 c m$ is rotating about its axis at the rate of $3 rpm$ . The torque required to stop after $2 π$ revolutions isNEET 2019 (All India)

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Answer:

Solution:

From rotational kinematic equations,
$ω_{f}^{2} - ω_{i}^{2} = 2 α θ$
$0^{2} - {(3 \frac{2 π}{60})}^{2} = 2 α 2 π (2 π)$
$α = - \frac{1}{800} r a d s^{- 2}$
$∴$ Torque required $τ = |I α|$
$= \frac{2 {(4 \times 10^{- 2})}^{2}}{2} \times \frac{1}{800}$
$= \frac{16 \times 10^{- 4}}{800}$
$= 2 \times 10^{- 6} N m$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2019

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