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PhysicsRotationTorque / angular accelerationHard2 minPYQ_2019
PhysicsHardsingle choice

A particle of massmis moving along a trajectory given by
x=x0+a cosω1t
y=y0+b sinω2t
The torque, acting on the particle about the origin, att=0is:

Options:

Answer:
A
Solution:

x=x0+a cosω1t
y=y0+bsinω2t
ax=-a ω12cosω1t
ay=-b ω22sinω2t
Att=0,
F=ma=-aω12i^
And
r=x0+ai^+y0j^
Torque,τ=r×F
τ=x0+ai^+y0j^×-aω12i^
=my0aω12k^

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration
2mℹ️ Source: PYQ_2019

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