Physics - Rotation Question with Solution | TestHub

A wire of length $L$ is bent to form a circular ring of radius $R$, $\therefore 2\pi R=L$ or $R=\frac{L}{2\pi }$ Moment of inertia of the circular ring about its axis is $I=M{R}^2=\frac{1}{4{\pi }^2}M{L}^2$