An L -shaped object, made of thin rods of uniform mass density, is suspended with a string as shown in figure. If A B = B C , and the angle made by A B with downward vertical is θ , then:

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TestHub · Accepted Answer

At equilibrium, the centre of mass will be below the point of suspension.

Taking torque about point O,

$m g \frac{l}{2} \sin θ + m g (l \sin θ - \frac{l}{2} \cos θ) = 0$

$\Rightarrow \frac{3 l}{2} \sin θ = \frac{l}{2} \cos θ$

$\Rightarrow \tan θ = \frac{1}{3}$

$\Rightarrow θ = {t a n}^{- 1} \frac{1}{3}$

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