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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Medium2 minPYQ_2016

PhysicsMediumsingle choice

A light rod of length, $l$ has two masses, $m_{1}$ and $m_{2}$ attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass isNEET 2016 (Phase 2)

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Answer:

Solution:

$x_{1} = \frac{m_{2} l}{m_{1} + m_{2}}$ and $x_{2} = \frac{m_{1} l}{m_{1} + m_{2}}$ .

$I = m_{1} x_{1}^{2} + m_{2} x_{2}^{2} = \frac{m_{1} m_{2}}{m_{1} + m_{2}} l^{2}$ .

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2016

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