A solid cylinder of mass 50 k g and radius 0.5 m is free to rotate about horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in

Question

A solid cylinder of mass 50 k g and radius 0.5 m is free to rotate about horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions s - 2 NEET 2014

TestHub · Accepted Answer

In this question we have to calculate tension

Given M = 50 kg

R = 0.5 m

angular acceleration = 2 revolution/ $s^{2}$

Now, Balancing the Torque

$(T) \times (R) = (\frac{M R^{2}}{2}) (α)$

$T = (\frac{M R}{2}) (α) = (\frac{50 \times 0.5}{2}) (2 \times 2 π) = 157 N$

So, the tension will be 157 N

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