Physics - Rotation Question with Solution | TestHub

The moment of inertia for a solid sphere along its diameter is $$I_{\text{diameter }}=\frac{2}{5}M{R}^2$$ Moment of inertia about a tangent touching to its surface, $$I_{\text{tangent }}=I_{\text{diameter }}+M{R}^2$$ (using theorem of parallel axes) $$=\frac{2}{5}M{R}^2+M{R}^2=\frac{7}{5}M{R}^2$$