Start Free Mock LoginAlready registered? Login here

Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationHard2 minPYQ_2011

PhysicsHardsingle choice

The instantaneous angular position of a point on a rotating wheel is given by the equation $Q (t) = 2 t^{3} - 6 t^{2}$ The torque on the wheel becomes zero atNEET 2011 (Screening)

Options:

Answer:

Solution:

According to question, torque, $τ = 0$ Its means that, $α = 0$ $α = \frac{d ^{2} θ}{d t ^{2}}$ Given So $θ (t) = 2 t^{3} - 6 t^{2}$ $\frac{d θ}{d t} \frac{d ^{2} θ}{d t ^{2}} 12 t - 12 t = 6 t^{2} - 12 t = 12 t - 12 (∵ α = \frac{d ^{2} θ}{d t ^{2}} = 0) = 0 = 1 s$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2011

Doubts & Discussion

Loading discussions...