Physics - Rotation Question with Solution | TestHub

Moment of inertia of the whole system about the axis of rotation will be equal to the sum of the moments of inertia of all the particles.$I=I_1+I_2+I_3+I_4$ $\therefore I=m_1{r}_1^2+m_2{r}_2^2+m_3{r}_3^2+m_4{r}_4^2$ $I=(1\times 0)+(2\times 0)+\left(3\times 3^2\right)+4(-2{)}^2$ $I=0+0+27+16=43\mathrm{kg}-{\mathrm{m}}^2$