Physics - Rotation Question with Solution | TestHub

The moment of inertia of uniform circular disc about an axis through its centre and normal to its plane $I_{\mathrm{CG}}=\frac{1}{2}M{R}^2$ According to theorem of parallel axis, the moment of inertia of the uniform circular disc about an axis passing from the edge of the disc fand normal to the disc, $I=I_{\mathrm{CG}}+M{R}^2=\frac{1}{2}M{R}^2+M{R}^2=\frac{3}{2}M{R}^2$