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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Medium2 minPYQ_2008

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Side of an equilateral triangle is $l$ . Three point masses, each of magnitude $m$ , are placed at the three vertices of the triangle. Moment of inertia of this system about one side of the triangle as axis is given by

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Solution:

Distance of corner mass from opposite side $= r$ $r^{2} = l^{2} - (\frac{l}{2})^{2} = \frac{3 l ^{2}}{4} I = m r^{2} = \frac{3}{4} m l^{2}$

Stream:AIIMSSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2008

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