A uniform rod AB of length I and mass m is free to rotate about point A . The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is m l 2 /3 , th

Question

A uniform rod AB of length I and mass m is free to rotate about point A . The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is m l 2 /3 , the initial angular acceleration of the rod will be NEET 2007

TestHub · Accepted Answer

Given that moment of inertia about A is I = m l 3 /3 Now, torque about A is given as ​ τ = F × r τ = m g 2 1 ​ I α = m g 2 1 ​ 3 m l 2 ​ α = m g 2 1 ​ α = 2 l 3 g ​ ​

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