Physics - Rotation Question with Solution | TestHub

The moment of inertia of the given system that contains 5 particles each of mass $=2\mathrm{kg}$ on the rim of circular disc of radius 0.1 m and of negligible mass is given by $=\text{ MI of disc }+\text{ MI of particle }$ Since the mass of the disc is negligible therefore, MI of the system $=$ MI of particle $=5\times 2\times (0.1{)}^2=0.1\mathrm{kg}{\mathrm{m}}^2$