A body attains a height equal to the radius of the Earth when projected from Earth' surface. The velocity of the body with which it was projected is :-

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Energy conservation between the surface and the highest point (height R, i.e. distance 2R from the centre): $\frac{1}{2} m v^{2} = G M_{e} m (\frac{1}{R} - \frac{1}{2 R}) = \frac{G M _{e} m}{2 R}$ .

So $v = \frac{G M _{e}}{R}$ .

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