Physics - Kinematics Question with Solution | TestHub

Given $x=2+2t+4t^2$ and $y=4t+8t^2$.

Eliminate t: $y=2(2t+4t^2)=2(x-2)$, i.e. $y=2x-4$.

The path is a straight line. (A) is correct, (C) is wrong.

$a_x=\frac{d^{2}x}{d{t}^2}=8,a_y=\frac{d^{2}y}{d{t}^2}=16$ - both constants.

The acceleration is uniform. (B) is correct, (D) is wrong.