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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium3 minQB

PhysicsMediumnumerical

A body is thrown straight up at 20 m/s; air drag equals $c u^{2}$ with $c / m = 0.005$ SI. The speed with which it returns to the point of projection is about: (Take $g = 9.8 m / s^{2}$ )

Answer:

18.20

Solution:

$u^{'} = \frac{20}{1 + 0.005 \times 400/9.8} = \frac{20}{1.204} = \frac{20}{1.097} = 18.2 m / s$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 3mℹ️ Source: QB

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