In the figure the block on the smooth table is set into motion in a circular orbit of radius r around the centre hole. The hanging mass is identical to the mass on the table and remains in equilibrium. Neglect friction. The string connecting the two blocks is massless and inextensible. Select the correct answer(s).

Question

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Hanging block in equilibrium, so T = mg

For the table block

$T = m ω^{2} r \Rightarrow ω = \frac{g}{r}$

$K = \frac{1}{2} m ω^{2} r^{2} = \frac{m g r}{2}$

Tension passes through the hole, so its torque about the hole is zero and L is conserved

The table block accelerates centripetally, so D is wrong

Answer: A, B, C

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Options:(select one or more)

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