Two bodies are thrown simultaneously from the same point, one straight up and the other at 30° to the horizontal, each with speed 20 m/s. Neglecting air drag, the distance between the bodies after 3 s is: (Answer in m.)
Answer:
60
Solution:
$d = v_{0} t 2 (1 - sin θ_{0})$
$= 20 \times 3 \times 2 \times 0.5$
$= 60 m$

Question

Two bodies are thrown simultaneously from the same point, one straight up and the other at 30° to the horizontal, each with speed 20 m/s. Neglecting air drag, the distance between the bodies after 3 s is: (Answer in m.)

Answer:

60

Solution:

$d = v_{0} t 2 (1 - sin θ_{0})$
$= 20 \times 3 \times 2 \times 0.5$
$= 60 m$

TestHub · Accepted Answer

d = v 0 ​ t 2 ( 1 − sin θ 0 ​ ) ​ = 20 × 3 × 2 × 0.5 ​ = 60 m

Physics - Kinematics Question with Solution | TestHub

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