Physics - Unit & Dimension Question with Solution | TestHub

$V=\pi r^{2}l$

$=\pi {(0.046\mathrm{c}\mathrm{m})}^2(21.7\mathrm{c}\mathrm{m})$

$=0.1443112{\mathrm{c}\mathrm{m}}^3$

The radius 0.46 mm has two significant figures, so round to two significant digits.

$V=0.14{\mathrm{c}\mathrm{m}}^3$