The period of oscillation of a simple pendulum is T = 2 π L / g . The measured value of L is 25.0 cm known to 1 mm accuracy and the time for 100 oscillations is found to be 120 s using a wrist watch o

Question

The period of oscillation of a simple pendulum is T = 2 π L / g . The measured value of L is 25.0 cm known to 1 mm accuracy and the time for 100 oscillations is found to be 120 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g (in percent)?

TestHub · Accepted Answer

Δ g g = Δ L L + 2 Δ t t = 0.1 25.0 + 2 ( 1 120 ) = 0.004 + 0.0167 = 0.0207 Thus the percentage error in g is about 2.1%.

Physics - Unit & Dimension Question with Solution | TestHub

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