A boy throws a ball upward with a speed of 26 m/s; the wind gives it a constant horizontal acceleration of 1 m / s 2 . For the ball to return to the point of release, it must be thrown at an angle to

Question

A boy throws a ball upward with a speed of 26 m/s; the wind gives it a constant horizontal acceleration of 1 m / s 2 . For the ball to return to the point of release, it must be thrown at an angle to the vertical of: (Take g = 10 m / s 2 )

TestHub · Accepted Answer

Zero horizontal displacement needs v x ​ = 2 a t ​ ; flight time t = g 2 v y ​ ​ . So tan θ = v y ​ v x ​ ​ = g a ​ = 10 1 ​ . (Consistency: v x 2 ​ + v y 2 ​ = ( 2.58 ) 2 + ( 25.87 ) 2 = 676 = ( 26 ) 2 . )

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