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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumnumerical

The acceleration time graph of a particle is shown in the figure. What is the velocity (in m/s) of particle at $t = 8 s$ if its initial velocity is 3 m/s ?

Answer:

7.00

Solution:

Velocity change is the signed area under the acceleration-time graph.

$Δ v_{0 \to 4} = \frac{1}{2} (4) (4) = 8 m/s$

$Δ v_{4 \to 8} = - (4) (1) = - 4 m/s$

$Δ v = 8 - 4 = 4 m/s$

$v (8) = v (0) + Δ v = 3 + 4 = 7 m/s$

Subject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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