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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsRelativeMedium3 minQB

PhysicsMediuminteger

A stone is dropped from a cliff 80 m high. Two seconds later a second stone is projected vertically downward with speed $u$ . If both stones reach the ground together, $u$ equals: (Take $g = 10 m / s^{2}$ )

Answer:

Solution:

First stone:
$t_{1} = 2 \times 80/10 = 4 s$ ;
second stone:
$t = 2 s$
with
$80 = 2 u + \frac{1}{2} \times 10 \times 4$ ,
so
$u = 30$
m/s.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Relative

⏱ 3mℹ️ Source: QB

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