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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minQB

PhysicsMediumsingle choice

A uniform rod is released from its vertical position with its bottom on a smooth surface. If v is the speed of the centre of mass of the rod and $ω$ is its angular velocity when it makes an angle $θ$ with the horizontal, then :-

Options:

Answer:

Solution:

No horizontal force, so the centre of mass moves vertically

Height of the centre of mass

$y = \frac{ℓ}{2} sin θ$

$v = \frac{d y}{d t} = \frac{ℓ}{2} cos θ \frac{d θ}{d t}$

$v = \frac{ω ℓ}{2} cos θ$

Answer: C

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: QB

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