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PhysicsMediumnumerical

A body starts from rest and moves for 'n' seconds with uniform acceleration 'a', its velocity after n seconds is 8 m/s. The displacement of the body in last 3 seconds is 15 m. Find the value of $a$ .

Answer:

1.41

Solution:

$v = u + a t$

$an = 8$ ...(i)

$15 = \frac{1}{2} a [n^{2} - (n - 3)^{2}]$

$15 = \frac{1}{2} a (6 n - 9)$

With $a = \frac{8}{n}$ :

$\frac{4}{n} (6 n - 9) = 15$

$24 n - 36 = 15 n$

$n = 4$

so $a = 2 m/ s^{2}$ .

$a = 2 = 1.41$

Answer: 1.41

Subject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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