Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minQB
PhysicsEasynumerical

The distance advanced by the screw of a screw gauge is2 mmin4rotations. Its cap is divided into50divisions. There is no zero error. If the screw reads3divisions on the main scale and32divisions on the cap, then the diameter (inmm) of the wire is

Answer:
1.82
Solution:

pitch =2/4

LC =2/450= .01 mm

diameter = 3 × 0.5 + 32 × .01

=1.5 + .32

= 1.82 mm

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...