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Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

For a screw gauge least count of the main scale is $1 m m .$ Find the minimum number of divisions on the circular scale so that it can measure a diameter of $5 μm$

Options:

Answer:

Solution:

Least count of screw gauge $= 5 μm$

$L . C = \frac{pitch}{no . of div on circular scale}$

$5 μm = \frac{1 mm}{N}$

$N = 200$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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